File diff r28800:381a234fb097 → r28801:c5b7832cf53a
src/strgen/strgen_base.cpp
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@@ -16,7 +16,7 @@
 
#include "../table/control_codes.h"
 

	
 
#include "strgen.h"
 
#include <charconv>
 

	
 

	
 
#include "../table/strgen_tables.h"
 

	
 
@@ -756,8 +756,8 @@ void StringReader::ParseFile()
 

	
 
	/* For each new file we parse, reset the genders, and language codes. */
 
	MemSetT(&_lang, 0);
 
	strecpy(_lang.number_format, "00,000,000,000,000,000,000", lastof(_lang.number_format));
 
	strecpy(_lang.number_abbreviations, "3=00,000,000,000,000,000{NBSP}k|6=00,000,000,000,000{NBSP}m|9=00,000,000,000{NBSP}bn|12=00,000,000{NBSP}tn|15=00,000{NBSP}Qa|18=00{NBSP}Qi", lastof(_lang.number_abbreviations));
 
	strecpy(_lang.digit_group_separator, ",", lastof(_lang.digit_group_separator));
 
	strecpy(_lang.digit_group_separator_currency, ",", lastof(_lang.digit_group_separator_currency));
 
	strecpy(_lang.digit_decimal_separator, ".", lastof(_lang.digit_decimal_separator));
 

	
 
	_cur_line = 1;
 
@@ -980,113 +980,3 @@ void LanguageWriter::WriteLang(const Str
 
		}
 
	}
 
}
 

	
 
static const std::string_view NBSP_TOKEN = "{NBSP}";
 

	
 
static std::string ReplaceNBSP(std::string string)
 
{
 
	for (;;) {
 
		auto iter = string.find(NBSP_TOKEN);
 
		if (iter == std::string::npos) break;
 

	
 
		string.replace(iter, NBSP_TOKEN.size(), NBSP);
 
	}
 
	return string;
 
}
 

	
 
/**
 
 * Parse the \c NumberFormatSeparators out of the given format string, with the expected number of digits.
 
 *
 
 * Different cultures have different ways to separate their numbers when they get really big. In the Western world
 
 * these are often called thousands separators which come every three digits counted from the back. The actual
 
 * separator differs per language/country. In Chinese, Japanese and Korean they add a character every four digits
 
 * counted from the back, and this character differs for each spot as it denotes "ten thousand", "hundred million",
 
 * etc. In the Indic numbering system (Indian subcontinent), the first separator is after three digits counted
 
 * from the back, but the next separators are given every two digits.
 
 *
 
 * So, there's no simple single parameter that you can add to the digit grouping character that is already
 
 * configured. The simplest solution is just defining what character to place between each of the digits, i.e what
 
 * characters separate each of the digits. These are the \c NumberFormatSeparators.
 
 *
 
 * To define these, you simply write a string of \c length zeros and then add any characters in between at the right
 
 * locations so the digit grouping is correct. When formatting numbers, it will start at the appropriate digit and
 
 * continue from there with separators.
 
 *
 
 * Examples of formats are "00,000,000,000,000,000,000" and "0000{NBSP}0000{NBSP}0000{NBSP}0000{NBSP}0000".
 
 *
 
 * @param separators The separators to fill; it will be cleared first.
 
 * @param format The format that is going to be read.
 
 * @param length The number of digits that are expected in this format.
 
 * @return An \c std::optional with the error message, or \c std::nullopt when the parsing went without problems.
 
 */
 
std::optional<std::string> ParseNumberFormatSeparators(NumberFormatSeparators &separators, std::string_view format, size_t length)
 
{
 
	separators.fill({});
 
	size_t seen_zeros = 0;
 

	
 
	auto it_separator = separators.rbegin();
 
	auto iter = format.find_last_of('0');
 
	while (iter != std::string_view::npos && it_separator != separators.rend())  {
 
		seen_zeros++;
 

	
 
		*it_separator = ReplaceNBSP(std::string(format.substr(iter + 1)));
 
		++it_separator;
 

	
 
		format = format.substr(0, iter);
 
		iter = format.find_last_of('0');
 
	}
 

	
 
	if (seen_zeros != length) return fmt::format("Unexpected number of digits ({} vs {}) in format string: [{}]", seen_zeros, length, format);
 

	
 
	return std::nullopt;
 
}
 

	
 
/**
 
 * Parse the \c NumberAbbreviations out of the given input string.
 
 *
 
 * In some places in the UI numbers are getting really big yet their exact value is not that important. For example
 
 * in the graphs of company values. For this you want more compact number, e.g. 123 m for 123.456.789. However, due
 
 * to the grouping of digits differing in different cultures, see \c ParseNumberFormatSeparators, there are many
 
 * different ways of grouping digits.
 
 *
 
 * This function builds up a lookup table of these abbreviations by power of ten. The input will be a list of
 
 * definitions per power separator by a pipe character (|). Each definition is the power of ten and and the
 
 * associated number format with DIGITS_IN_UINT64_T - power digits, separated by the equals sign (=).
 
 *
 
 * For example, for English it defines every third power of ten with subsequently smaller number formats:
 
 * 3=00,000,000,000,000,000{NBSP}k|6=00,000,000,000,000{NBSP}m|9=00,000,000,000{NBSP}bn|12=00,000,000{NBSP}tn|15=00,000{NBSP}Qa|18=00{NBSP}Qi
 
 *
 
 * @param abbreviations The table to write the abbreviations in; is will be cleared before filling.
 
 * @param input The input format to parse.
 
 * @return An \c std::optional with the error message, or \c std::nullopt when the parsing went without problems.
 
 */
 
std::optional<std::string> ParseNumberAbbreviations(NumberAbbreviations &abbreviations, std::string_view input)
 
{
 
	abbreviations.clear();
 

	
 
	std::map<int, std::string_view> abbreviation_map;
 
	do {
 
		std::string_view part = input.substr(0, input.find_first_of('|'));
 
		input.remove_prefix(std::min(part.size() + 1, input.size()));
 

	
 
		auto equals = part.find_first_of('=');
 
		if (equals == std::string_view::npos) return fmt::format("Part [{}] does not have an '='", part);
 

	
 
		std::string_view power_sv = part.substr(0, equals);
 
		int power = 0;
 
		if (std::from_chars(power_sv.data(), power_sv.data() + power_sv.size(), power).ec != std::errc{}) return fmt::format("Power [{}] is not a number", power_sv);
 
		if (power >= DIGITS_IN_UINT64_T || power <= 0) return fmt::format("Power {} is not allowed", power_sv);
 

	
 
		abbreviation_map[power] = part.substr(equals + 1);
 
	} while (!input.empty());
 

	
 
	for (auto iter = abbreviation_map.rbegin(); iter != abbreviation_map.rend(); ++iter) {
 
		NumberFormatSeparators separators;
 
		auto result = ParseNumberFormatSeparators(separators, iter->second, DIGITS_IN_UINT64_T - iter->first);
 
		if (result.has_value()) return result;
 

	
 
		abbreviations.emplace_back(PowerOfTen(iter->first), separators);
 
	}
 

	
 
	return std::nullopt;
 
}